(x-1)*(x+5)=x^2+4x-2

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Solution for (x-1)*(x+5)=x^2+4x-2 equation: 



(x-1)(x+5)=x^2+4x-2

We move all terms to the left:

(x-1)(x+5)-(x^2+4x-2)=0

We get rid of parentheses

-x^2+(x-1)(x+5)-4x+2=0

We multiply parentheses ..

-x^2+(+x^2+5x-1x-5)-4x+2=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+5x-1x-5)-4x+2=0

We get rid of parentheses

-1x^2+x^2+5x-1x-4x-5+2=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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